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Author Topic: A CHALLENGE!!! MATH!!!  (Read 133 times)

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Offline majd

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A CHALLENGE!!! MATH!!!
« on: February 14, 2020, 12:12:55 am »
OK so, let me explain how this works. basically you get a 4 digit number, and you have to make an expression using math symbols that is true. for example if your number is 4297, it would be 4-2=9-7. you cannot introduce any numbers to the 4 you have and they must stick in that order. YOU CANT JUST DERIVE THAT SHIT SO U CAN JUST GET 0. also must use equal. no greater or less than bs!!

who ever can solve this in 3 days will get an orange name color or chat color!

3156

u have 3 days good luck
« Last Edit: February 14, 2020, 12:17:41 am by majd »

Offline baseballattix

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Re: A CHALLENGE!!! MATH!!!
« Reply #1 on: February 14, 2020, 12:24:50 am »
Γ(3!+1)=(5+([ζ(-6)]!))!

Offline majd

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Re: A CHALLENGE!!! MATH!!!
« Reply #2 on: February 14, 2020, 12:26:43 am »
Γ(3!+1)=(5+([ζ(-6)]!))!

uhh ok so the first part can be broken down to Γ(7) which is equal to 6!, or 720.

the second part is more complex. its 5 + the zeta function of -6 which is 0. by taking the factorial, you just get 1. so 5+1 factorial is 6!

SO U WIN!!! WHAT WOULD U LIKE???
« Last Edit: February 14, 2020, 12:29:03 am by majd »

Offline baseballattix

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Re: A CHALLENGE!!! MATH!!!
« Reply #3 on: February 14, 2020, 12:30:41 am »
No need for either maybe do a different giveaway instead

Offline Eskimo

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Re: A CHALLENGE!!! MATH!!!
« Reply #4 on: February 14, 2020, 07:46:27 am »
It seems like my time to leech
Γ(3!+1)=(5+([ζ(-6)]!))!
I’ll take orange chat color

 

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